by **Keeley** » Sat Oct 07, 2017 10:14 pm

That "the finished velocity will swap" basically works whilst the lots are equivalent and the collision is head-on. Shoot a pool cue ball at contemporary at an merchandise ball, and the cue ball stops and the item ball strikes. Shoot a BB gun at a bowling ball, and the BB bounces. there is regularly a formula, even with the undeniable fact that I to locate it much less complicated to keep in mind the physics, and specially easier to verify the disaster in the middle-of-mass rest physique. in the middle-of-mass physique, the go out velocity for a very-elastic collision is truly symmetrical. The each and every go out %. is the unfavourable of the the get right of entry to %.. So, the stairs are: a million. Compute v_cm = (m1*v1 + m2*v2) / (m1 + m2). it truly is the middle of mass velocity. (finished momentum)/(finished mass) 2. Set v1_cm = v1 - v_cm, v2_cm = v2 - v_cm. those are the get right of entry to velocities in the middle of mass physique. 3. Set v1'_cm = -v1_cm, v2'_cm = - v2_cm. those are the go out velocities in the middle of mass physique. 4. Set v1' = v1'_cm + v_cm, v2' = v2'_cm + v_cm. it truly is all. This unravels to: v1' = -(v1 - v_cm) + v_cm = 2*v_cm - v1 v1' = 2*(m1*v1 + m2*v2)/(m1 + m2) - v1 So, there's a components. the item to keep in mind is that the project was once uncomplicated and symmetrical in the middle of mass physique...and that's clever for added themes than basically a a million-dimensional head-on collision.