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What Is The Total Kinetic Energy Of The Objects After The Collision, If The Collision Is Perfectly Elastic?

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What Is The Total Kinetic Energy Of The Objects After The Collision, If The Collision Is Perfectly Elastic?

Postby Glendale » Sat Oct 07, 2017 6:58 am

Object A has of mass 7.20 kilograms, and object B has a mass of 5.75 kilograms. The two objects move along a straight line toward each other with velocities +2.00 meters/second and -1.30 meters/second respectively. What is the total kinetic energy of the objects after the collision, if the collision is perfectly elastic?

a. 19.3 joules

b. 21.9 joules

c. 38.5 joules

d. 43 joules

e. 50.8 joules
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What Is The Total Kinetic Energy Of The Objects After The Collision, If The Collision Is Perfectly Elastic?

Postby Keeley » Sat Oct 07, 2017 10:14 pm

That "the finished velocity will swap" basically works whilst the lots are equivalent and the collision is head-on. Shoot a pool cue ball at contemporary at an merchandise ball, and the cue ball stops and the item ball strikes. Shoot a BB gun at a bowling ball, and the BB bounces. there is regularly a formula, even with the undeniable fact that I to locate it much less complicated to keep in mind the physics, and specially easier to verify the disaster in the middle-of-mass rest physique. in the middle-of-mass physique, the go out velocity for a very-elastic collision is truly symmetrical. The each and every go out %. is the unfavourable of the the get right of entry to %.. So, the stairs are: a million. Compute v_cm = (m1*v1 + m2*v2) / (m1 + m2). it truly is the middle of mass velocity. (finished momentum)/(finished mass) 2. Set v1_cm = v1 - v_cm, v2_cm = v2 - v_cm. those are the get right of entry to velocities in the middle of mass physique. 3. Set v1'_cm = -v1_cm, v2'_cm = - v2_cm. those are the go out velocities in the middle of mass physique. 4. Set v1' = v1'_cm + v_cm, v2' = v2'_cm + v_cm. it truly is all. This unravels to: v1' = -(v1 - v_cm) + v_cm = 2*v_cm - v1 v1' = 2*(m1*v1 + m2*v2)/(m1 + m2) - v1 So, there's a components. the item to keep in mind is that the project was once uncomplicated and symmetrical in the middle of mass physique...and that's clever for added themes than basically a a million-dimensional head-on collision.
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What Is The Total Kinetic Energy Of The Objects After The Collision, If The Collision Is Perfectly Elastic?

Postby Worton » Sun Oct 08, 2017 10:53 pm

TKE = 1/2 (MV^2 + mv^2) = (1/2)*(7.2*2^2 + 5.75*1.3^2) = 19.25875 = 19.3 J ANS a.
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What Is The Total Kinetic Energy Of The Objects After The Collision, If The Collision Is Perfectly Elastic?

Postby Franki » Tue Oct 10, 2017 1:42 pm

In perfectly elastic collision the kinetic energy remains conserved. Calculate 1/2 m1u1^2 + 1/2 m2 u2^2

14.4 + 21.49 = 35.89 J
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